Mathematics, 30.01.2020 23:51 erik1franks
Two similar hexagons have corresponding heights of 3 m and 4 m. if the area of the smaller hexagon is 13 m2, what is the area of the larger hexagon? (round your answer to one decimal place.)
Answers: 3
![\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\ -------------------------------\\\\ \cfrac{smaller}{larger}\qquad \cfrac{3}{4}=\cfrac{\sqrt{13}}{\sqrt{a}}\implies \cfrac{3}{4}=\sqrt{\cfrac{13}{a}}\implies \left( \cfrac{3}{4} \right)^2=\cfrac{13}{a} \\\\\\ \cfrac{3^2}{4^2}=\cfrac{13}{a}\implies \cfrac{9}{16}=\cfrac{13}{a}\implies a=\cfrac{16\cdot 3}{9}](/tpl/images/0487/6724/6fc84.png)
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Two similar hexagons have corresponding heights of 3 m and 4 m. if the area of the smaller hexagon i...
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