What is the completely factored form of f (x)=6x^3-13x^2-4x+15?

f(x)= (x+1)(2x-3)(3x-5)

Step-by-step explanation:

f(x) = 6x³ - 13x² - 4x + 15

This could also be written as:

f(x) = 6x³ - 19x² + 6x² + 15x - 19x + 15

f(x) = 6x² - 19x² + 15x + 6x² - 19x + 15

f(x) = x(6x² - 19x + 15) + 1(6x² - 19x + 15)

f(x) = (x + 1)(6x² - 19x + 15)

f(x) = (x + 1)(6x² - 10x - 9x + 15)

f(x) = (x + 1)(2x(3x - 5) - 3(3x - 5))

f(x) = (x + 1)(2x - 3)(3x - 5)

f(x)= (x+1)(2x-3)(3x-5)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

do your own work and don"t cheat.

step-by-step explanation: