The diameter of circle q terminates on the circumference of the circle at (3,0) and (3,-7). write the equation of the circle in standard form. show all of your work for full credit.

The standard form of the circle equation is (x−h)2+(y−k)2=r2.
Given the points of the diameter : (3,0) and (3,-7) we can compute that the diameter of the circle is equal to 7 units, r = 3.5. h is equal then to 3 and k is equal to -3.5
substituting, the formula becomes
(x-3)^2 + (y-3.5)^2 = 12.25

The answer for you question is b