Complete each statement in the steps to solve x2 – 6x – 7 = 0 using the process of completing the square. isolate the constant by both sides of the equation. add to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced. write the trinomial x2 – 6x + 9 as squared. use the square root property of equality to get x – 3 = ± . isolate the variable to get solutions of –1 and 7.
answers:
adding 7 to
9
x-3
4

Answers: Using the process of completing the square:

1. Isolate the constant by adding 7 to both sides of the equation:

x^2-6x-7+7=0+7

x^2-6x=7

2. Add 9 to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced:

x^2-6x+9=7+9

x^2-6x+9=16

3. Write the trinomial x2 – 6x + 9 as squared:

(x-3)^2 = 16

4. Use the square root property of equality to get x – 3 = ±4 .

sqrt[ (x-3)^2 ] = ± sqrt(16)

x-3 = ±4

5. Isolate the variable to get solutions of –1 and 7.

x-3 = ±4

x-3+3 = ±4+3

x = ±4+3

x1=-4+3→x1=-1

x2=+4+3→x2=7

1 adding 7 to

2 9

3 x-3

4 4

Step-by-step explanation:

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

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step-by-step explanation: