Astudy of one thousand teens found that the number of hours they spend on social networking sites each week is normally distributed with a mean of 30 hours. the population standard deviation is 2 hours. what is the 95% confidence interval for the mean?

Given:

Sample Mean = 30
Sample size = 1000
Population Standard deviation or σ=2
Confidence interval = 95%

to compute for the confidence interval

Population Mean or μ= sample mean ± (z×SE)

where:

SE→ Standard Error

SE=σ√n= 30√1000=0.9486

Critical Value of z for 95% confidence interval =1.96

μ=30±(1.96×0.9486)
μ=30±1.8594

Upper Limit

μ = 30 + 1.8594 = 31.8594

Lower Limit

μ = 30 − 1.8594 = 28.1406

28.1406<u<31.8594

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all