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which are the coordinates of the vertices of the reflected figure when triangle def is reflected across the y-axis?

a.
d'(0, 3)
e'(3, 1)
f'(–3, –2)

b.
d'(0, 3)
e'(3, –1)
f'(–3, –2)

c.
d'(0, –3)
e'(–3, 1)
f'(–3, –2)

d.
d'(3, 0)
e'(3, –1)
f'(–3, –2)

da freeck kinda math is this just drop out

step-by-step explanation:

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.