The line containing the diagonal of a square whose vertices are a(-3, 3), b(3, 3), c(3, -3), and d(-3, -3). find two equations, one for each diagonal.

Attached to the answer is a graph of the square, based on the points given. From there you can easily guess the equations of the diagonal lines.

However, you do not need a graph in order to solve the problem. 

AC and BD are two pairs of points diagonally across from one another. This is because the pairs do not share the same x or y value. 

Based on the equation of the line:
 
We must find the slope(m) and the y-intercept(b).

Finding slope (m):
Lets use the equation below:


Line AC:


∴ m = -1
∴

Line BD:


∴ m = 1
∴ 

Find y-intercept (b):
In order to find the y-intercept(b) of the line, we must plug in a point that is on that line.

Line AC:
y = -1x + b
3 = -1(-3) + b
3 = 3 + b
b = 0 

Line BD:
y = 1x + b
3 = 1(3) + b
3 = 3 + b
b = 0

Therefore, the equations for the diagonals are as follows:



Hope this helps!