What are the zero(s) of the function f(x)=4x2-36x over x-9?

x=0 is the zero of the given function

Step-by-step explanation:

To find zeros of the function we replace f(x) with 0

then we solve for x

Now we factor the numerator 4x^2 -36x

Cancel out x-9 at the top and bottom

0=4x (divide by 4 on both sides)

x=0

So x=0 is the zero of the given function

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.

ratio is 2 : 9

the answer is three

13.5 : 3