According to the 2000 u. s. census bureau, 49.65% of texas residents were male. if one texan was selected at random in 2000, what is the probability she was female? a. 0.4965 b. 0.5 c. 0.5035 d. 49

0.5035

Step-by-step explanation:

Given: According to the 2000 U.S. Census Bureau, 49.65% of Texas residents were male.

Thus the percent of male in Texas = =49.65%

When we divide percent by 100, we get the fraction of male to the total population=0.4965

⇒  If one Texan was selected at random in 2000, what is the probability she was male P(M)=0.4965

Since, there are only two events according to gender (Male and Female)

∴ P(M)+P(F)=1

⇒ P(F)=1-P(M)

⇒ P(F)=1-0.4965

⇒ P(F)=0.5035

Hence, If one Texan was selected at random in 2000, the probability she was female =0.5035

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3