The point (5, −2) is on the terminal ray of angle θ, which is in standard position. without evaluating, explain how you would find the values of the six trigonometric functions.

1. Check the picture attached.

let P, M, N be the points :P(5, -2), M(5, 0), N(0, -2)

ABP is the angle with measure ∅, where BA is the initial ray and BP the terminal ray.

2. m(PNM)=∅ as can be easily checked

In triangle PNM, NP=5, PM=2 and NM= units

3. let opp=opposite side, adj=adjecent side, hyp=hypothenuse

sin ∅ = opp/hyp=

cos ∅ = adj/hyp=

tan ∅ = opp/adj=2/5

cot ∅ = adj/opp=5/2

sec ∅ = hyp/adj=

csc ∅ = hyp/opp=

Then why is the question on here if you know the answer