What four consecutive odd integers have a sum of 336?

Call x is the first number. 
The second is x+2
The third is x+4
The forth is x+6
=> x + (x+2) + (x+4) +(x+6) = 336
<=> 4x +12 = 336
<=> 4x = 324
<=> x = 81
=> the first is 81; the second is 83, the third is 85 and the forth is 87

Im sorry i cant answer it : ( im so sorry