Find the equation in slope intercept form for the line that is perpendicular to the line 10x- 5y=3 and passes through the point (4,-3)

Hello:

10x -5y =3

5y = 10x-3

y =2x -3/5( slope : 2)
the equation is : y = ax+b
the slope is a : a×(2) = -1( perpendicular to a line with a slope of2)
a = -1/2          y=(-1/2)x+b
the line that passes through (4, -3) : -3 = (-1/2)(4)+b
b = -1
 the equation is :  y  = (-1/2)x-1

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation: