Atravel agency offers two dallas outings. plan a includes hotel accommodations for three nights and two pairs of texas rangers baseball tickets worth a total of $557. plan b includes hotel accommodations for five nights and four pairs of rangers baseball tickets worth $974. find the cost of one night’s hotel accommodations and the cost of one pair of baseball tickets.

We let x as the cost of one night’s hotel accommodations and y as the cost of one pair of baseball tickets. For plan A, we can generate the equation as 3x + 2y = $557 and for plan B; 6x + 4y = $1114

Using elimination, we can write the two as:

3x + 2y = 557

5x + 4y = 974

Multiply both eq. 1 by 2 to eliminate y

2(3x + 2y = 557)2

6x + 4y = 1114

We now have

6x + 4y = 1114

5x + 4y = 974        ⇒ subtract

X = 140

Substitute x to either equation to get the value of y

3(140) + 2y = 557

2y = 557 – 420

2y = 137

Y = 68.5

unpaid balance is : $149.99-$50 = $99.99 new balance = 149.99+2.62-50 = $102.61 finance charge = 99.99- 0.21/12= $1.75 new balance = 99.99+1.75 = $101.74 average daily balance method average daily balance= 3399.70/30 = $113.32 finance charge = $ 0.21/12ă—113.32 = $1.98 new balance = $149.99-50+1.98 = $101.97