Find the illegal values of b in the fraction 2b² + 3b - 10 over b² - 2b - 8 .
a. b = −2...
Mathematics, 30.12.2019 17:31 lif3isanenigma
Find the illegal values of b in the fraction 2b² + 3b - 10 over b² - 2b - 8 .
a. b = −2 and −4
b. b = −2 and 4
c. b = −5, −2, 2, and 4
d. b = −5 and 2
Answers: 2
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