What is the equation of the line perpendicular to y=3x+2 that passes through the point (0, 2)?

The equation is y = -1/3x + 2.

Point Slope Form : y - y1 = m(x - x1)
Given: (0,2) and y = 3x + 2

When the line is perpendicular, flip the slope upside down and make it into its opposite ( - to +).

Slope: -1/3

y - 2 = -1/3(x - 0)
y - 2 = -1/3x + 0
+ 2 + 2

y = -1/3x + 2

X= -5because this is a single step equation so you would just have to divide -16 both sides for x to equal your solution