The exact times in seconds, of four sprinters from a school track meet are as follows

sprinter a -132.38
sprinter b - 132.31
sprinter c - 132.29
sprinter d - 132.25

if the stopwatch used was precise only to the tenths place, which sprinters time is different from the others

sprinter a b c or d

sprinter A

sprinters b, c, and d would all round to 132.30

b- 132.31 rounds to 132.30

c- 132.29 rounds to 132.30

d- 132.25 rounds to 132.30

*look at the last digit, less than 5 you go to lower, 5 or more you go up!

(for example 33 would round to 30, 37 would round to 40)

hope this helps <3

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)