Determine the implied domain of the function found in the first step. express your answer in interval notation.

We can re-write the equation √(1-x) - 2y = 2 → - 2y = 2 - √(1-x)

→ 2y = - 2 + √(1-x) → and y = [ - 2 + √(1+x)]/2

Tis function "exists" as long as the radical is > or = to zero:
1+x > or = 0 → x>-1
{x ∈ R for x> =0}

That is so true, i can’t believe how true this is