The number of rainbow smelt in lake michigan had an average rate of change of −19.76 per year between 1990 and 2000. the bloater fish population had an average rate of change of −92.57 per year during the same time. if the initial population of rainbow smelt was 227 and the initial population of bloater fish was 1,052, after how many years were the two populations equal?

For Edgenunity

The linear function that models the population of bloater fish is y2 =

-92.57 x + 1,052

The linear equation that determines when the two populations were equal is

-19.76 x + 227= -92.57x + 1052

The solution is x = 11.33 years

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions