From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. if the base of the cliff is 205 feet from the boat, how high is the cliff (to the nearest foot)?

Let the distance of the cliff from the boat be y and height of the top of the cliff be x.

As per the statement:

From a boat on the lake, the angle of elevation to the top of a cliff is 26°1'. If the base of the cliff is 205 feet from the boat.

⇒y = 205 feet,

We have to find the high is the cliff i,e x.

Using tangent ratio:

See the diagram as shown below:

Opposite side = x feet

adjacent side = 205 feet

Using conversion:

then;

Substitute these values we have;

Multiply both sides by 205 we have;

ft

Therefore, 100 ft high is the cliff(to the nearest foot)

step-by-step explanation:

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