In △mno, m = 20, n = 14, and m∠m = 51°. how many distinct triangles can be formed given these measurements?

One obtuse scalene triangle

Step-by-step explanation:

Given that in a triangle MNO side m =20, side n =14 and angle m = 51

Angle N = sin inverse of (nsin M/m) =32.957 degrees

Angle O = 180-M-N =96.043 degrees

Side o = 25.592

There is one triangle only.

This is because angle N can have two values 32.957 or 147.043

But if m = 51 other angle cannot be 147.043 hence there is only one value for angle N.

When there is only one value for angle N, angle O also can have only one value

So no of triangles = 1

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right