What is the slope-intercept form of the equation of the line that passes through (7, 3) and is perpendicular to the line of the equation y = (-1/15)x – 10.

Y = -1/15x - 10. The slope here is -1/15. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocl of a number, flip the number and change the sign. So our perpendicular line will need a slope of 15see how I flipped -1/15 and turned it to -15/1and changed the sign, making it 15/1 or just 15.

y = mx + b
slope(m) = 15
(7,3)...x = 7 and y = 3
now we sub and find b, the y int
3 = 15(7) + b
3 = 105 + b
3 - 105 = b
-102 = b

so ur perpendicular equation is : y = 15x - 102 <==

Im pretty sure it is a