Acertain survey conducted had a population proportion of at most 22% for people who agreed. what is the confidence level if 20% of the people sampled agreed, and the standard error of the proportion is ±1%?

The formula for the population proportion is:

n = p ± Zc 

where p = confidence level = 0.2

 n = proportion = 0.22

= standard error = 0.01

Finding for Zc:

.20+(.01)=.22

Zc = 2

Referring to Critical value table for standard normal curve, a Zc value of 2 is equivalent to 95% Confidence Level.

95% Confidence Level

15 units use socratic

step-by-step explanation: 15 units

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50