What are the solutions of 3x2 + 6x + 6 = 0

–2 ± i
–2 ± 2i
–1 ± i
1 ± i

C) Quick way:

3x^2+6x+6=0 ---> x^2+2x+2=0,

sum of solutions is the 'x' coefficient multiplied by -1:  (-1+i)+(-1-i)=-2-->2
Product is the independent term: (-1+i)(=1+i) = (-1)^2-i^2 = 1+1=2

Takes longer to write it down!