Acertain bacteria is growing at a rate of 4 percent each day. if the culture of bacteria has 5,000 bacteria today, how many bacteria will be present 10 days from now?

Since we are given that the rate of growth of the bacteria is 4% then, the amount of bacteria is 1.04 times that of the amount the previous day. This can be mathematically expressed as,

                      A(t) = (Ao) x (1.04)^(t/n)

where A(t) is the amount after t days, Ao is the original amount, t is the number of days and n is the basis of the rate reported. 

Substituting the known values,
 
                   A(t) = 5000 x (1.04)^(10/1)
                      A(t) = 7401.22

Thus, the amount of bacteria after 10 days is approximately equal to 7401. 

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