Identify both the x- and y-intercepts of the linear equation graphed on the coordinate plane above. use the intercepts to write an equation of the line in point-slope form, slope-intercept form, and general form of a linear equation.
complete your work in the space provided or upload a file that can display math symbols if your work requires it. in your work, be sure to include the coordinates for both intercepts and the equations of the line in all three formats.

The x int (where the line crosses the x axis) is (-2,0)
the y int (where the line crosses the y axis) is (0,-2)

(-2,0)(0,-2)
slope = (-2 - 0) / (0 - (-2) = -2/2 = -1

y = mx + b
slope(m) = -1
use either of ur points (-2,0)...x = -2 and y = 0
sub and find b
0 = -1(-2) + b
0 = 2 + b
-2 = b

so ur equation in slope intercept form is : y = -x - 2

y = -x - 2
x + y = -2
x + y + 2 = 0 <== general form

there can be 2 answer for point slope form...
y - y1 = m(x - x1)
slope(m) = -1
(-2,0)...x1 = -2 and y1 = 0
sub
y - 0 = - (x - (-2)
y - 0 = -(x + 2) <=== point slope form

y - y1 = m(x - x1)
slope(m) = -1
(0,-2)...x1 = 0 and y1 = -2
sub
y - (-2) = - (x - 0)
y + 2 = - (x - 0) <== point slope form

You need to include the original coordinates of the triangle to answer this. and how much does it translate (move left right up down)