Afireworks company has two types of rockets called zinger 1 and zinger 2. the polynomial -16t2 + 150t gives the height in feet of zinger 1 at t seconds after launch. the polynomial -16t2 + 165t gives the height of zinger 2 at t seconds after launch. if the rockets are launched at the same time and both explode 6 seconds after launch, how much higher is zinger 2 than zinger 1 when they explode?

When they explode, Zinger 2 will be higher than Zinger 1 by; 90 ft

We are given the following polynomials to represent the height of both rockets as;

For Zinger 1; h(t) = -16t² + 150t

For Zinger 2; h(t) -16t² + 165t

We are told that the rockets are launched at the same time. Thus, after 6 seconds;

For Zinger 1; h(6) = -16(6²) + 150(6)

h(6) = -576 + 900

h(6) = 324 ft

For Zinger 2; h(6) = -16(6²) + 165(6)

h(6) = -576 + 990

h(6) = 414 ft

Thus, Zinger 2 is higher by;

414 - 324 = 90 ft

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Zinger 1 = -16(6)^2 +150(6) = 324 feet

Zinger 2 = -16(6)^2 + 165(6) = 414 feet

414-324 = 90 feet

Zinger 2 is 90 feet higher

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

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