Consider a political discussion group consisting of 9 democrats, 7 republicans, and 3 independents. suppose that two group members are randomly selected, in succession, to attend a political convention. find the probability of selecting no democrats

Well, first you would add up how many objects you have to select from

9 democrats + 7 Republicans + 3 Independents = 19 total people
so then you would put how many people you can have over that number
so since we don't want any Democrats it would be 10/19 (.52)
and that tells you the chances of not picking one the first time

then, since that person cannot be selected again, we remove them from the pool, making it only 18 people to pick from and 9 people you want picked so once again you put 9/18 (.50), then you take those, (in decimal form) and multiply them (.26) then convert it to a fraction by moving the decimal to the right two and have 26% chance of no Democrats 

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