What are the real zeroes of x^3 + 6 x^2 – 9x – 54?

Here is the process you can follow to get the real zeroes

x³ + 6x² - 9x - 54
(x³ + 6x²) + (-9x - 54)
x²(x + 6) + (-9)(x+6)
(x² - 9)(x + 6)
(x + 3)(x - 3)(x + 6)

The zeroes are -3, 3, and -6

I hope this helps you :D

What are the answer choices?

Hnmmmn not sure