You roll two standard number cubes. what is the probability that the sum is odd, given than one of the number cubes shows a 1? show your work.

When you roll 2 standard number cubes there are 36 different sums.
This probability is different because they give us a restriction with the "given that one f the cubes shows a one". The denominator becomes the number total number of rolls with a 1, and the numerator is the sum is odd.
P (odd sum is, given 1 number is a 1) = 6/11

That’d be 9 years or something