Where are the asymptotes for the following function located? f(x)=14/(x-5)(x+1) a. x=-1 and x=5 b. x=-1 and x=14 c. x=1 and x=-5 d. x=14 and x=5

F(x) = 14/(x - 5)(x + 1)
The vertical asymptotes are determined by the denominator.
Set each factor of the denominator equal to zero and solve.
x - 5 = 0                                        x + 1 =0
add 5 to both sides                      subtract 1 from both sides
x = 5                                            x = -1
LETTER A

The correct answer is $90

Equatorial triangle and obtuce angle