Iam confused about this question in trigonometry:

use AE and CE to find the angle

AE = 20, CE = 6

 so the angle FOR CAE = tan^-1(6/20) = 16.7 degrees

 to Find DF

a^2 = b^2 +c^2-2abcos(A)

a^2 = 10^2 + 14^2 -2(14)(10)cos(16.7)

a^2 = 30

sqrt((30)=5.47 rounded to 5.5

EF =

a^2 = b^2 +c^2-2abcos(A)

a^2 = 20^2 + 14^2 -2(14)(20)cos(16.7)

a^2 = 64

sqrt(64)=8

2

step-by-step explanation:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.