Triangle xyz is located at x (−2, 1), y (−4, −3), and z (0, −2). the triangle is then transformed using the rule (x−1, y+3) to form the image x'y'z'. what are the new coordinates of x', y', and z'?

The given points are X (−2, 1), Y (−4, −3), and Z (0, −2)

By using the rule (x − 1, y + 3) the points then become:

X′ (− 2 − 1, 1 + 3), Y′ (− 4 − 1, − 3 + 3), and Z′ ( 0 −1, − 2 + 3)

X′ (− 3, 4), Y′ (− 5, 0), and Z′ (− 1, 1)

If the corresponding vertices of both triangles were connected with line segments then we should get exact congruent triangles with just x- and y-coordinates transformed or we can say that:

△XYZ=△X′Y′Z′

X′ (− 3, 4), Y′ (− 5, 0), and Z′ (− 1, 1)

the answer will be the last one

6(h+1)/2=a

a=area

step-by-step explanation:

its the same thing as a square or rectangle but after multiplying two sides you need to divide it by two.