Atriangular sign has a base that is 44 cm and an altitude that is 40 cm. if one litre of paint covers 44000 cm squared, how many signs can be painted with one litre of paint? (both sides must be painted)

The triangular sign has a base of 44cm and a height of 40cm.

Use these values in the formula for the area of a triangle.



Thus one side of the sign is 880 cm².
Since both sides of the sign must be painted, you must paint 880×2 = 1760 cm² for an entire sign.

How many signs would 44,000 cm² be?
44,000 ÷ 1760 = 25 signs.

Thus one litre of paint covers 25 signs.

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.