Which is the equation of the line with slope 5 that contains point (-2, -3)
a. y + 2 = 5(x – 3) b. y + 3 = 5(x + 2) c. y – 3 = 5(x – 2) d. y – 2 = 5(x – 3)

The answer is y = 5x + 7

here's how you get it:

Start with the base   y = mx + b

then imput the points and the slope:

-3 = 5 ( -2 ) + b

Then solve for b

-3 = 5 ( -2 ) + b

-3 = -10 + b

-b = -7

b = 7

so the equation is:

y = 5x + 7

the answer is 1/4

step-by-step explanation: