Elizabeth brought a box of donuts to share. there are two-dozen (24) donuts in the box, all identical in size, shape, and color. five are jelly-filled, 5 are lemon-filled, and 14 are custard-filled. you randomly select one donut, eat it, and select another donut. find the probability of selecting two jelly -filled donuts in a row.

This is a probability problem with two dependent events and conditional probability. Note that after the first donut is chosen, it is not replaced into the data set, so only 23 donuts remain. If we set A=selection of a lemon-filled, and B=selection of a custard-filled, then P(A and B) = P(A)*P(B|A), where P(B|A) means the probability of B happening given that A has already occurred.P(A) = 8/24 = 1/3 = 0.333333P(B|A) = 12/23 = 0.521739P(A and B) = 1/3(12/23) = 12/69 = 0.1739130435 or 17.4%

https://www.wyzant.com/resources/answers/296921/find_the_probability_of_selecting_a_a_lemon_filled_d...

20y5 times 2 is 1010 times -2 is -20, plus y