There is a 65% chance that mom will order chinese take-out for dinner, 45% chance that she will take you to a movie, and a 70% chance that she will order both chinese take out and take you to a movie. what is the chance that she will order chinese take out or take you to a movie ? (hunt: probability of unions )

Yeah, thanks:

P(AUB)=P(A)+P(B)-P(A and B) = .65+.45-.7 = .4, 40%

P(A)=0.65
P(B)=0.45
P(AnB)=0.70
P(AnB)=0.65+0.45-0.70=0.40
40% chance that mom will order chinese food and take you to a movie

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to