Find an equation in standard form for the hyperbola with vertices at (0, ±4) and asymptotes at y = ±1 divided by 3.x.

We are given a=4 and a/b = 1/3 for this problem. Therefore we can imply that 4/b = 1/3. If we then set up 4/b = 1/3 we get b = 12. Then, you can plug 4 in for a^2 and 12 in for b^2 and you get y^2/16 - x^2/144 = 1. Hope this helps!

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!