Which situation will have the greatest number of possible outcomes? a. the number of 5-digit zip codes, where the digits cannot be repeated. b. the number of 5-digit zip codes, where the digits increase. c. the number of 5-digit zip codes, where the digits can be repeated. d. the number of 5-digit zip codes, where the digits are the same.

It would be C, with C you have approximately 100,000 combinations. You had 10 with D 0-9. I would think you have 6 combinations with B not completely sure. And A is approximately 30,240 combinations

A.
10 digits
so there are 10*9*8*7*6 or 30240 combinations

B.
ok, the highest one would be
56789
the lowest is
01234
this is interesting, but it is definitely less that the first option because 54321 is not an option

C.
can be repeated
that is 10⁵ or 100,000 differnt combos

D.
same?
only 10
00000
11111
22222
33333
44444
etc, you get it

so the most one would be C

Ithink its 126 hope its