For a daily airline flight between two cities, the number of pieces of checked luggage has a mean of 380 and a standard deviation of 20. what number of pieces of checked luggage is 3 standard deviations above the mean?

The answer is 440 pieces of checked luggage

Step-by-step explanation:

Mean = 380

Standard deviation = 20

No. of pieces of checked luggage for 1 standard deviation = 20 pieces

Therefore, Mean for 3 standard deviations above the mean = 3 × 20 = 60

Now, number of pieces of checked luggage 3 standard deviations above the mean = Mean for 1 standard deviation + Mean for 3 standard deviations above the mean

⇒ 380 + 60 = 440 pieces

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.