The probability of a randomly selected car crashing during a year in a certain country is 0.04770.0477. if a family has threethree cars, find the probability that at least one of them has a car crash during a year. is there any reason why the probability might be wrong?

P(having one crash) = 0.0477
P(having NO crash) = 1- 0.0477 = 0.9523

ⁿCₓ(p)ˣ. (1-p)ⁿ⁻ˣ
n= number of cars
x = number of crashes
p = 0.0477 (1 crash)
1-p = 0.9523 (NO crash:
 Probability of NO crashes at all:

³C₀(0.0477)⁰(0.9523)⁽³⁻⁰⁾

³C₀(1)(0.9523)³ = 0.9523³ = 0.8636 Then P(NO CRASH) = 0.8636

P(at LEAST one crash) = 1 - 0.8636

P(at LEAST one crash) = 0.136

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