Aright triangle has leg lengths of x units and 3(x + 1) units. its hypotenuse measures 25 units. find the leg lengths. urgent! brainliest to the best answer!

You get the hypothenuse by doing √a²+b² = c

So....



Square both terms

x² + (3x+3)² = 625

x² + 9x² + 18x + 9 - 625 = 0

10x² + 18x - 616 = 0

x₁,₂ = (-b±√Δ)/2a

Δ = b²-4ac

You call a 10, b 18 and c -616

x1,2 = (-18±√18²-4*10*-616)/2*10

x1,2 = (-18±√324+24640)/20

x1,2 = (-18±√24964)/20

x1,2 = (-18±158)/20

x1 = -18+158/20 = 140/20 = 7

x2 = (-18-158)/20 = -176/20 = -44/5

Pick the first solution

So one leg is 7 and the other is 3(7+1) = 3(8) = 24

Let's verify √24²+7² = √576+49 = √625 = 25