For this question, determine if the equation is always, sometimes, or never true. if the equation is sometimes true, determine the numbers that make it true.

the equation is: 6y + 5 = 4y + 5 and -2(6 - 10n) = 10(2n - 6)

If I've understood correctly,
First eq'n:
True only when y = 0
[simply rearrange the eq'n to solve for y]
Second eq'n:
Never true
[when you expand and simplify you will get some two different integers equated to each other which is incorrect; the integers will vary depending on how and how much simplifying you do]

7for nonmembers i think