Parents sold 275 tickets for a fundraiser at the community center. student tickets cost $3, and adult tickets cost $5. the total value of tickets sold is $1,025. which system of equations represents the problem?
1. 3x + y = 275
x + 5y = 1025

2. y = 275

3x + y = 1025
x + y = 275

3. 3x + 5y = 1025
y = x + 275

x + y = 1025

hence, the system of equations is:

                x+y=275

and         3x+5y=1025

let 'x' denote the number of student ticket sold.

and y denote the number of adult tickets sold.

now, it is given that:

parents sold 275 tickets for a fundraiser at the community center.

i.e. x+y=275.

also,

student tickets cost $3, and adult tickets cost $5.

the total value of tickets sold is $1,025.

hence, we have second equation as:

3x+5y=1025.

hence, the system of equations is:

                x+y=275

and         3x+5y=1025

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is symmetric about the line y = 120,000.

step-by-step explanation: