Every day, the number of network blackouts has a distribution (probability mass function)
x | 0 | 1 | 2
p(x)| 0.7| 0.2| 0.1
a small internet trading company estimates that each network blackout results in a $500
loss. compute expectation and variance of this company’s daily loss due to blackouts.

i computed this e(x)= .4 , varx= .44, but i don't know how i can find the answer?

the answer is
e(y ) = 200 dollars,
var(y ) = 110, 000 squared dollars.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts