Fiona decides to join a gym for a minimum of one month to train for a triathlon. the gym charges a joining fee of $100 and a monthly fee of $38. if x represents the number of months that fiona is a member of the gym, the equation below can be used to determine c, her total membership fee for that duration of time: 100 + 38x = c fiona has allocated a maximum of $328 to spend on her gym membership. which number line shows the possible number of months that fiona can be a member of the gym?

x = 6

Step-by-step explanation:

Given : Fiona decides to join a gym :

A joining fee of $100

A monthly fee of $38

x represents the number of months.

Fiona has allocated a maximum of $328 to spend on her gym        membership

Her total membership fee for that duration of time: 100 + 38x = C

Solution :

It is given that Fiona has allocated a maximum of $328 to spend

So, C = $328

Putting this value in equation 100 + 38x = C

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Thus, x = 6 is number line that shows the possible number of months that Fiona can be a member of the gym.

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.