What is the solution to the following system?

3x+2y+z=20

x-4y-z=-10

2x+y+2z=15

a. (2, 3, 4)

b. (4, 3, –2)

c. (4, 3, 2)

d. (6, 7, –2)

C. (4, 3, 2)

Step-by-step explanation:

Given :

To Find: Solution:

  -1

     --2

  --3

Substitute the value of z from 1 in 2 and 3

So in 2 ,  

 ---4

So, in 3 ,  

  -5

Now solve 4 and 5

Substitute the value of x from 4 in 5

Now substitute the value of y in 4

Now substitute the value of x and y in 1 to get value of z

Thus The solution is (4,3,2)

Hence Option c is correct.

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this