Four circles, each with a radius of 2 inches, are removed from a square. what is the remaining area of the square? (16 – 4π) in.2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2four circles, each with a radius of 2 inches, are removed from a square. what is the remaining area of the square? (16 – 4π) in.2 (16 – π) in.2 (64 – 16π) in.2 (64 – 4π) in.2

unit square.

Step-by-step explanation:

Here, four circle are removing from a square from the square of edge 8.

Since, The area of the square= square unit  ( because, area of square=side×side)

The area of a circle with radius 2 = square unit.

The area of four circle of radius 2= square unit.

According to the question, these four circle are removed by the above square.

Therefore remaining area of the square after removing these four circle=area of the square- area of four circle of radius 2= square unit.

three-fourths of an hour

36÷48=0.75

0.75=

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)