Find the area of a parallelogram with sides of 6 and 12 and an angle of 60°.

a: 72√3 sq. units
b: 36√3 sq. units
c: 12√3 sq. units

I think I got it. Correct me if I am wrong.

Parallelogram diagram I believe down below. We must find the height and then the area using Pythagorean theorem. Since the green shaded part is a 30-60-90 triangle, the base is 1/2 the hypotenuse, therefore it is 3. Now we calculate the height with it.

A^2 + B^2 = C^2
A^2 + 3^2 = 6^2
    A^2 + 9 = 36
          A^2 = 27
              A = 3√3

Therefore the height is 3√3

Now calculate the area using A = bh

A = bh
   = (12)(3√3)
   = 36√3

So the area is 36√3 square units.

I cannot be sure of this answer because you did not provide a diagram.

Answer:

13.46

step-by-step explanation:

16.80 x .20 = 13.46