Solve 3x2 + 13x = 10
a. x = two over three and x = −5
b. x = 3 and x = −3
c. x = −2 and x = five over three
d. x = −7 and x = 13

We want to solve the quadratic equation 3x² + 13x = 10.

Write the equation as
3x² + 13x - 10 = 0

Use the quadratic formula to obtain
x = (1/6) [ -13 +/- √{13² - 4*3*(-10)} ]
   = (1/6) [-13 +/- √289]
   = (1/6) [-13 +/- 17]
x = -30/6 = -5
or
x = 4/6 = 2/3

The solution is x = 2/3 and -5.

 a

If you make it a little more clear i can answer it