Aball is thrown from a height of 140 feet with an initial downward velocity of 8 ft/s. the ball's height h (in feet) after t seconds is given by the following.

h=140-8t-16t^2

how long after the ball is thrown does it hit the ground?

round your answer(s) to the nearest hundredth.
(if there is more than one answer, use the "or" button.)

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

x-150=475   x=625

step-by-step explanation:

if the bike after the sale ($150) is $475 then just simply add 150 to 475.